A cable elevator leaves from the ground floor and moves vertically. After a very short initial

acceleration it maintains a constant velocity of $$velevator$.$ When the elevator reaches height $$h$$ above

the ground, a small piece falls off the elevator. At the time when this piece hits the ground, calculate

the height of the elevator above ground. You can neglect air resistance on the falling

Use values:

L $=12$m

aB $=5\mathrm{.}2$ m$/$s$^2$

vB $=8\mathrm{.}2$ m$/$s

Calculate the angular acceleration $[$rad$/$sec$^2]$ if the ladder. Counterclockwise acceleration is a positive number. Report your answer to three significant figures.