Question: A capacitor using a new dielectric will be tested by connecting it in the circuit shown above with two resistors of resistance R and
A capacitor using a new dielectric will be tested by connecting it in the circuit shown above with two resistors of resistance R and a power supply of potential difference E. The ammeter A has negligible resistance, and the current through the voltmeter V is negligible. The internal resistance of the battery is negligible. Select and justify the measurements that can be used to determine the capacitance C of the capacitor. (A) Use the measurement of the voltmeter at regular intervals of time as the capacitor charges, because this can be used to determine the time constant for the circuit, and thus the capacitance. (B) Use the steady state measurement of the voltmeter, because this can be used to determine the charge stored on the capacitor, and thus the capacitance. (C) Use the measurement of the ammeter at regular intervals of time as the capacitor charges, because this can be used to determine the time constant for the circuit, and thus the capacitance. (D) Use the steady state measurement of the ammeter, because this can be used to determine the charge stored on the capacitor, and thus the capacitance. (E) Use the steady state measurement of both the ammeter and the voltmeter, because this can be used to determine the charge stored on the capacitor and the time constant, and thus the capacitance. RS R
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Option E is correct As it allows for the determination of c... View full answer
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