A capacitor with capacitance C is connected in parallel to two inductors: inductor 1 with inductance L , and inductor 2 with inductance 2 L , as shown in the figure. The capacitor is charged up to a voltage V , at which point it has a charge q . There is no current in the inductors. Then the switch is closed. (Figure 1)

Part A.  Since the two inductors are in parallel, the voltage across them is the same at any time. Hence, V 1= V 2= X 1 I 1= X 2 I 2, where X 1 and X 2are the reactance of inductors 1 and 2, and I 1 and I 2 are the currents through them. Use this equality to express I 1 in terms of I 2.

Part B.  What is the effective inductance L eff of the inductors 1 and 2 in the circuit?

Part C.  Find the maximum current I 1max through inductor 1.

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2L (') C: 2L (') C: