A certain CD$-$ROM disk can store approximately $6\mathrm{.}0{10}^2$ megabytes of information, where ${10}^6$ bytes $=1$ megabyte. If an average word requires $9\mathrm{.}0$ bytes of storage, how many words can be stored on one disk?

None of the above choices are correct.

$6\mathrm{.}7{10}^7$ words

$2\mathrm{.}1{10}^7$ words

$2\mathrm{.}0{10}^9$ words

$5\mathrm{.}4{10}^9$ words