Question $9(1$ point$)$

E

A certain CD$-$ROM disk can store approximately $6\mathrm{.}0102$ megabytes of information, where $106$ bytes $=1$ megabyte. If an average word requires $9\mathrm{.}0$ bytes of storage, how many words can be stored on one disk?

$6.7{10}^7$ words

$5\mathrm{.}4{10}^9$ words

$2\mathrm{.}1{10}^7$ words

$2\mathrm{.}0{10}^9$ words

Question $9(1$ point$)$

E

A certain CD$-$ROM disk can store approximately $6\mathrm{.}0102$ megabytes of information, where $106$ bytes $=1$ megabyte. If an average word requires $9\mathrm{.}0$ bytes of storage, how many words can be stored on one disk?

$6.7{10}^7$ words

$5\mathrm{.}4{10}^9$ words

$2\mathrm{.}1{10}^7$ words

$2\mathrm{.}0{10}^9$ words

Question $9(1$ point$)$

E

A certain CD$-$ROM disk can store approximately $6\mathrm{.}0102$ megabytes of information, where $106$ bytes $=1$ megabyte. If an average word requires $9\mathrm{.}0$ bytes of storage, how many words can be stored on one disk?

$6.7{10}^7$ words

$5\mathrm{.}4{10}^9$ words

$2\mathrm{.}1{10}^7$ words

$2\mathrm{.}0{10}^9$ words