Question: A circular ring (radius = 50 mm) is used to determine the surface tension of a liquid. The plane of the ring is positioned so
- A circular ring (radius = 50 mm) is used to determine the surface tension of a liquid. The plane of the ring is positioned so that it is parallel to the surface of the liquid. The ring is immersed in the liquid and then pulled upward, so a film is formed between the ring and the liquid. In addition to the rings weight, an upward force of 10102 N required to lift the ring to the point where it just breaks free of the surface. Calculate the surface tension of the liquid, give the result in both N/m and dynes/cm. Note: Assume both sides (inside and outside) of the ring has the same diameter/radius and perimeter.
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