A clever engineer designs a "sprong" that obeys the force law Fx$=$q$($x$$xe$)3$Fx$=$q$($x$$xe$)3,$ where xexe is the equilibrium position of the end of the sprong and qq is the sprong constant. For simplicity, we'll let xe$=0$mxe$=0$m$.$ Then Fx$=$qx$3$Fx$=$qx$3.$

Part A

What are the units of qq$?$

NNN$/$m$3$N$/$m$3$N$/$mN$/$mN$/$m$2$N$/$m$2$

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Part B

Find an expression for the potential energy of a stretched or compressed sprong.

Express your answer in terms of the variables qq and xx$.$

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U$($x$)$U$($x$)=$

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