A client is paying you $$\frac{1150\mathrm{.}50}{o}z$ of Pt to weigh out $1000Pt$ samples. The contract between you the client states that the weight of $Pt$ for each sample is defined to be:

$($Weight of the sample.$)-($The average noise in the measurement.$)-2x($The standard deviation in the noise of the measurement.$)$

If the signal to noise of the measurement could be increased to $25000,$estimate how much more money would you make on the contract?

Assume your starting signal to noise is $300.$ Assume the same signal as in question $2.$ Assume all the Pt samples will have a similar weight. Both questions $1$ and $2$ are pasted below for your reference. Do not use scientific notation. $1oz.=28\mathrm{.}3595g$ Use all figures. Do not use units or dollar signs.

Question $2$: If the average noise for the previous question $($see below$)$ was $0\mathrm{.}506g,$ what would the signal to noise be$?$

Question $1$: A sample of $Pt$ is weighed $5$ times with the following results: $50\mathrm{.}121g,50\mathrm{.}289g,50\mathrm{.}003g,50\mathrm{.}241g,49\mathrm{.}910g$