A closed loop level run is performed between two points of known elevation. When

the elevations are calculated and checked, an error of $0\mathrm{.}059$ ft is found from what

was expected. Using the allowable misclosure of $C=0\mathrm{.}02\sqrt[\phantom{2}]{n}($where $C$ is allowable

misclosure and n is the number of setups$),$ what is the minimum number of setups

required to allow for this much error?

$9$

$3$

$4$

$5$