A concrete mixture is specified as $1$:$2$:$5$:$5$ by loose volume with $26$ liters of water per bag of cement to produce a satisfactory mixture. It is required to produce $2\mathrm{.}0$ cu$.$m of concrete. Assume $1$bag of cement has theoretical volume of $0\mathrm{.}0283$cu$.$m

Cement: SG$=3\mathrm{.}10,$ e$=52\%$

Sand: SG$=2\mathrm{.}62,$ e$=40\%$

Gravel: SG$=2\mathrm{.}66,$ e$=37\mathrm{.}5\%$

How may bags of cement are required?

$11$

$13$

$15$

$17$

A concrete mixture is specified as $1$:$2$:$5$:$5$ by loose volume with $26$ liters of water per bag of cement to produce a satisfactory mixture. It is required to produce $2\mathrm{.}0$ cu$.$m of concrete. Assume $1$bag of cement has theoretical volume of $0\mathrm{.}0283$cu$.$m

Cement: SG$=3\mathrm{.}10,$ e$=52\%$

Sand: SG$=2\mathrm{.}62,$ e$=40\%$

Gravel: SG$=2\mathrm{.}66,$ e$=37\mathrm{.}5\%$

What is the weight of gravel$($kg$)$ required?

$2764\mathrm{.}149$

$2864\mathrm{.}149$

$2964\mathrm{.}149$

$2664\mathrm{.}149$