Question: A cone-shaped tank has a cross-sectional area that increases with its depth: A=(r^2h^2)/H^3. Show that the work to empty it is half the work for

A cone-shaped tank has a cross-sectional area that increases with its depth: A=(r^2h^2)/H^3. Show that the work to empty it is half the work for a cylinder with the same height and base.

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