Question: A continuous random variable X has a pdf of the form: f(x)=(424/27)x3, for 0.53 A continuous random variable X has a pdf of the form:

A continuous random variable X has a pdf of the form: f(x)=(424/27)x3, for 0.53

A continuous random variable X has a pdf of the form: f(x) = (424/27) xA3, for 0.53 < X < 0.76. Calculate the mean (mu) of X. Your answer: O O O O O O O O O 0.603 0.636 0.686 0.665 0.658 0.584 0.646 0.534 0.623 0.754

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