Question: A cosmic ray proton ( m p = 1 . 6 7 1 0 - 2 7 k g ) strikes the Earth near the

A cosmic ray proton (mp=1.6710-27kg) strikes the Earth near the equator with a vertical velocity of 2.8107ms. Assume that the horizontal component of the Earth's magnetic field at the equator is 30T. Calculate the ratio of the magnetic force on the proton to the gravitational force on it.
A cosmic ray proton ( m p = 1 . 6 7 1 0 - 2 7 k g

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