A cube with edge length L = 0.25 m and density Q = 0.88103 kg/m floats in equilibrium in a liquid of density = 15103 kg/m3, with the top of the cube a distance d above the liquid's surface, as shown in the figure. 91 Pc -L- P 33% Part (a) Enter an expression for the distance d, in terms of the defined quantities. d=QcL(Qm) * Attempts Remain A 33% Part (b) If the density of the cube is equal to the density of the liquid, how high, in meters, will the top of the cube be above the surface of the liquid? A 33% Part (c) The given values of edge length and densities, are L = 0.25 m, Qc = 0.88103 kg/m, and Q = 1.5103 kg/m. With these values, how high, in meters, is the top of the cube above the liquid's surface. d = || m sin() cos( tan() cotan() asin() acos() E > 7 89 1^^4 5 6 HOME 1 2 3 cosh() tanh() cotanh() + - 0 O Degrees Radians VO BACKSPACE DEL END CLEAR atan() acotan() sinh() Grade Summary Deductions Potential Submissions 0% 100% Attempts remaining: 100 (0% per attempt) detailed view