Question: A curve is given parametrically by the equations x = (1+t) , y =(1-t) .Find the equation of the tangent to the curve at the

 A curve is given parametrically by the equations x = (1+t)
, y =(1-t) .Find the equation of the tangent to the curve

A curve is given parametrically by the equations x = (1+t) , y =(1-t) .Find the equation of the tangent to the curve at the point where x = y . Hint: Use the chain-rule of differentiation to find the derivative. To find the point of intersection, use substitution method. Furthermore, find the value of using the given condition x = y , then, compute the corresponding value of x and y

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