A cylinder of volume 0.270 m contains 11.1 mol of neon gas at 19.8C. Assume neon...

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A cylinder of volume 0.270 m³ contains 11.1 mol of neon gas at 19.8°C. Assume neon behaves as an ideal gas. (a) What is the pressure of the gas? 100084.408 Pa (b) Find the internal energy of the gas. 40534.19 J (c) Suppose the gas expands at constant pressure to a volume of 1.000 m³. How much work is done on the gas? 73061.62 X The response you submitted has the wrong sign. J (d) What is the temperature of the gas at the new volume? 1084.44 K (e) Find the internal energy of the gas when its volume is 1.000 m³. 150125.997✔✔ J (f) Compute the change in the internal energy during the expansion. 109591.81 ✔ J (g) Compute AU - W. 36530.19 Your response differs from the correct answer by more than 10%. Double check your calculations. J (h) Must thermal energy be transferred to the gas during the constant pressure expansion or be taken away? The internal energy of the gas increases although it does work, i.e. it transfer energy to its surroundings. So there must be an additional energy transfer to the gas, such you get an net positive change in internal energy. A cylinder of volume 0.270 m³ contains 11.1 mol of neon gas at 19.8°C. Assume neon behaves as an ideal gas. (a) What is the pressure of the gas? 100084.408 Pa (b) Find the internal energy of the gas. 40534.19 J (c) Suppose the gas expands at constant pressure to a volume of 1.000 m³. How much work is done on the gas? 73061.62 X The response you submitted has the wrong sign. J (d) What is the temperature of the gas at the new volume? 1084.44 K (e) Find the internal energy of the gas when its volume is 1.000 m³. 150125.997✔✔ J (f) Compute the change in the internal energy during the expansion. 109591.81 ✔ J (g) Compute AU - W. 36530.19 Your response differs from the correct answer by more than 10%. Double check your calculations. J (h) Must thermal energy be transferred to the gas during the constant pressure expansion or be taken away? The internal energy of the gas increases although it does work, i.e. it transfer energy to its surroundings. So there must be an additional energy transfer to the gas, such you get an net positive change in internal energy.

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Heres the corrected solution with explanations a Pressure of the gas We can use the ideal gas law PV ... View the full answer