a$.$ Determine whether the Mean Value Theorem applies to the function $f(x)=-1-x^2$ on the interval $[-1,2].$

b$.$ If so$,$ find the point$($s$)$ that are guaranteed to exist by the Mean Value Theorem.

a$.$ Choose the correct answer below.

A$.$ No$,$ because the function is not continuous on the interval $-1,2,$ and is not differentiable on the interval $(-1,2).$

B$.$ Yes, because the function is continuous on the interval $-1,2$ and differentiable on the interval $(-1,2).$

C$.$ No$,$ because the function is continuous on the interval $-1,2,$ but is not differentiable on the interval $(-1,2)$

D$.$ No$,$ because the function is differentiable on the interval $(-2),$ but is not continuous on the interval $[-1,2].$

b$.$ Select the correct choice below and, if necessary, fill in the answer box to complete your choice

A$.$ The point$($s$)$ is$/$are $x=$

$($Simplify your answer. Use a comma to separate answers as needed.$)$

B$.$ The Mean Value Theorem does not apply in this case.