$($a$)$

Draw the vectors

a $=$

$3,2$

$,$ b $=$

$2,1$

$,$ and c $=$

$6,1$

$.$

The x$$y$-$coordinate plane is given. There are three vectors.

The first vector, labeled a$,$ starts at the origin and goes up and right.

The second vector, labeled b$,$ starts at the origin and goes down and right.

The third vector, labeled c$,$ starts where vector a ended and goes down and right to end where vector b ended.

The x$$y$-$coordinate plane is given. There are three vectors.

The first vector, labeled a$,$ starts at the origin and goes up and right.

The second vector, labeled b$,$ starts where vector a ended and goes down and right.

The third vector, labeled c$,$ starts at the origin and goes up and right to end where vector b ended.

The x$$y$-$coordinate plane is given. There are three vectors.

The first vector, labeled a$,$ starts at the origin and goes up and right.

The second vector, labeled b$,$ starts at the origin and goes down and right.

The third vector, labeled c$,$ starts at the origin and goes up and right.

The x$$y$-$coordinate plane is given. There are three vectors.

The first vector, labeled a$,$ starts at the origin and goes up and right.

The second vector, labeled b$,$ starts at the origin and goes up and left.

The third vector, labeled c$,$ starts at the origin and goes up and right.

$($b$)$

Find, by means of a sketch, scalars s and t such that

c $=$ sa $+$ tb$.$

$($Round your answers to one decimal place.$)$

s$$t$$

$($c$)$

Find the exact values of s and t$.$

s$=$