A fiber optic cable is like a light pipe made of glass with flat end faces. Light enters at an angle 0, refracts at the front face, and then bounces its way down the pipe. Determine the maximum angle, 0, for which the light rays incident on the end of a glass pipe (in the figure below) are subject to total internal reflection (TIR) along the walls of the pipe (not at the end face). Assume that the pipe has an index of refraction of n and that the outside medium is air (nair =1). TIR at walls of fiber air (n, =1) glass (nalass 0=? Note: Your must simplify your answer as much as possible, and it must be in terms of the given variables. Also, clearly label your angles! Hint #1: Don't let the 3D perspective above fool you. Here is a flatter version: TIR at walls of fiber air (n =1) glass (n = 0=? Hint #2: Here are some trig identities which might be useful for simplifying your answers: sin(90-0)=cos(0) cos(90-0)=sin(0) sin20+cos20=1