Question: For the equilibrium process shown below, the 255 MHz proton NMR spectrum showed two distinct environments for the alkene protons in the slow exchange
For the equilibrium process shown below, the 255 MHz proton NMR spectrum showed two distinct environments for the alkene protons in the slow exchange limit with a chemical shift difference of 1.5 ppm. Calculate the rate of exchange for these two environments. If coalescence occurs at -21 C calculate the activation energy for the process. Hb Hb. Ru- Ru MegP Hb- Me3P Hb AG* = 19.17 10.32 log k J mol-! T.
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