A force of 20 lb is required to hold a spring stretched 8 in. beyond its...

 

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A force of 20 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching it from its natural length to 11 in. beyond its natural length? According to Hooke's Law, the force required to maintain a spring stretched a units beyond its natural length is proportional to z. This means that f(x) = kx, for some constant k. Since our spring is stretched 8 in., which is equal to ft, we have 20- k Now, we can say that the work done in stretching the spring 11 in. = its natural length is given by the following. W lb/ft. - S.Th 11/12 W Hence, the work done is equal to the following. 11/12 00 dz ft-lb k. So ft beyond A force of 20 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching it from its natural length to 11 in. beyond its natural length? According to Hooke's Law, the force required to maintain a spring stretched a units beyond its natural length is proportional to z. This means that f(x) = kx, for some constant k. Since our spring is stretched 8 in., which is equal to ft, we have 20- k Now, we can say that the work done in stretching the spring 11 in. = its natural length is given by the following. W lb/ft. - S.Th 11/12 W Hence, the work done is equal to the following. 11/12 00 dz ft-lb k. So ft beyond

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