Question: A function fis depicted on the graph below on the interval -2,4. The interval -2,4is subdividedinto three intervals, I1=[-2,1],I2=[1,2] and I3=[2,4].We would like to find

A function fis depicted on the graph below on the interval -2,4. The interval -2,4is subdividedinto three intervals, I1=[-2,1],I2=[1,2] and I3=[2,4].We would like to find the best possible lowerand upper bounds for the integral offon the interval -2,4 using a combination of the left-endpoint,right-endpoint, midpoint, and trapezoidal rules.(a)(2 points) Which of the following integration methods provides the best possible lower bound forthe integral off over the interval I1=[-2,-1]?(b)(2 points) Which of the following integration methods provides the best possible upper bound forthe integral off over the interval I1=[-2,-1]?Left-endpoint ruleRight-endpoint ruleMidpoint ruleTrapezoidal rule(c)(2 points) Which of the following integration methods provides an exact value for the integral off over the interval I2=[-1,2]? Select all that apply.Left-endpoint ruleRight-endpoint ruleMidpoint ruleTrapezoidal ruleNone of these(d)(2 points) Which of the following integration methods provides the best possible lower bound forthe integral off over the interval I3=[2,4]?Left-endpoint ruleRight-endpoint ruleMidpoint ruleTrapezoidal rule(e)(2 points) Which of the following integration methods provides the best possible upper bound forthe integral off over the interval I3=[2,4]?

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