Question: A golf ball is hit upward, with an initial velocity of 63 meters per second, at an angle of 32 with respect to the

A golf ball is hit upward, with an initial velocity of 63 meters per second, at an angle of 32 with respect to the horizontal. The ball is hit from a height of 9 meters above the ground. The horizontal distance x from the starting point and the height y above the ground of the ball f seconds after it is hit are given by the parametric equations below. x= x-(vocos) y=-4.97+(vosine)+h Here vo is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the golf ball reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. seconds (b) What is the maximum height of the golf ball? Round your answer to the nearest tenth. meters

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