A golf ball is thrown on a golf course. The target is at 1 = 18.7...

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A golf ball is thrown on a golf course. The target is at 1 = 18.7 m and lower than the initial point by h = 1.7 m. The golfer lifts the ball at a theta = 54 deg angle. VA Ako B x e 1. Write the 6 equations of motion: acceleration, velocity, and position on x and y during the flight of the golf ball. 2. Using 2 equations at the point of Impact (point B), solve for VÀ and tÅ. 3. Find the velocity at B (VBx, VBy, and VB its magnitude). 4. Find the maximum height of the flight. 5. Draw the path of the flight, draw the vector velocity at A, at the max height, and at B. Include vector, components on x and y and angle for the 3 vectors. Check that your numerical answers make sense with your graph. Use 1 cm = 1 m for x-axis and y-axis. Use 1 cm = 5 m/s for the vectors velocity. In the box below, enter the magnitude of the velocity VA in m/s with one decimal. A golf ball is thrown on a golf course. The target is at 1 = 18.7 m and lower than the initial point by h = 1.7 m. The golfer lifts the ball at a theta = 54 deg angle. VA Ako B x e 1. Write the 6 equations of motion: acceleration, velocity, and position on x and y during the flight of the golf ball. 2. Using 2 equations at the point of Impact (point B), solve for VÀ and tÅ. 3. Find the velocity at B (VBx, VBy, and VB its magnitude). 4. Find the maximum height of the flight. 5. Draw the path of the flight, draw the vector velocity at A, at the max height, and at B. Include vector, components on x and y and angle for the 3 vectors. Check that your numerical answers make sense with your graph. Use 1 cm = 1 m for x-axis and y-axis. Use 1 cm = 5 m/s for the vectors velocity. In the box below, enter the magnitude of the velocity VA in m/s with one decimal.

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1 Equations of motion for the golf ball during its flight Acceleration in the xdirection ax ax 0 ass... View the full answer