Question: A hermetically sealed electric motor compressor combination with isentropic efficiency of 6 0 % , receives R 1 3 4 a vapour from an evaporator

A hermetically sealed electric motor compressor combination with isentropic efficiency of 60%, receives R134a vapour from an evaporator where the saturation temperature is -2C. The vapour leaves the evaporator with 2C of superheat and travels to the compressor in a well-insulated suction pipe. The cooling capacity achieved in the evaporator is 9.0+0.xkW where X is the last digit of one student number, e.g. student number is 3334568, so Q=8.8kW. The condenser saturation temperature is 44C. Refrigerant (R134a) leaves the condenser as a liquid sub cooled by 4C, and travels directly to the throttle without change in temperature:
a)(10 marks) Sketch the cycle on a pressure-enthalpy diagram with 60% isentropic efficiency compression. From your sketch provide the enthalpy values (read values from your plot) at each stage of the cycle. Using these values, determine the enthalpy change in the condenser, and evaporator?
b) As a comparative study, use the thermophysical properties table for R134a, calculate the net enthalpy change for an isentropic compression (in the compressor stage). Show the steps on how you obtain the enthalpy values.
A hermetically sealed electric motor compressor

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