A horizontal bar is attached to a wall. When a force of $1kN$ is applsed at point $A($Figure $1),$ the deflection at point $A$ is ${}_{AA}=0\mathrm{.}49mm.$ When a $1kN$ force is applied at point $B($figure $2),$ the

Learning Goal:

To use the principle of superposition to relate external axial loads on a bar to axial dieflections

Under certain conditions, the effect of complicated loads can be calculated by combining the effects of simple component loads. This is called the principle of superposition. This method can only be used when the intemal axial force $N$ in a body is linearty relatod to the displacement or extemal loading, and the deflections are small enough that the body's geometry does not change significantly.

II a complicated load can be expressed as a linear combination of the simpler loads, then the stress or displacement at a point will be the same linear combination of the corresponding responses in the simpter toads

deflection at point $A$ is ${}_{AB}=0\mathrm{.}23mm.($A given deformation due to a unit load is known as a flexibifity factor$)$

Part A $-$ Larger load

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}m$

What is the change in the length of the bar if there is a single load of $5\mathrm{.}6kN$ applied to the right at point $A?$ Use a positive value to indicate an increase in length

Express your answer in $mm$ to three significant figures.

Part B $-$ Combined loads

What is the change in the length of the bar if a load of $6kN$ is applied to the left at A and a load of $9\mathrm{.}2kN$ is applied to the right at $B?$ Use a positive value to indicate an increase in length Express your answer in $mm$ to three significant figures.

Only Part B please