A: I will use factor by grouping, A 3&2 5k Q The coefcient of k2 is B and the constant term os -9. The product of B and J? is -72. The factors of -?2 which sum to -6 are 6 and -12. This equation cannot by factored by grouping, No factor of 7'2 sum up to 6. soak? kQ=8k2 12k+kQ= 2k[4k+3] 3(4k+3] 2kf4k+3j 3(4k+3) Since the two quanties in parentheses are now identical that means we can factor out the common factors. [43: + 3) (2k 3} B: Factor by grouping. Using factor by grouping again. 3732+7ym2 y *Polynomial Degree:3 *Leading Term :I:2y *Leading Coefcient -1 Factor out 7 from T32+7 7 {11:2 + 1) Factor out \"I\" from :L*2y y y (:1:2 + l) 57me +1) y(:1:2 +1) Factor out the common term 3:2 + 1 (a:2 +1] (\"Fy}