A is an n xn matrix. Determine whether the statement below is true or false. Justify the answer. Finding an eigenvector ofA may be difficult, but checking whether a given vector u is in fact an eigenvector is easy. Choose the correct answer below. 0 A. The statement is false. Checking whether a given vector u is in fact an eigenvector is difcult because it requires checking that u is a nonzero vector, finding A' 1 , then finding if Au is a scalar multiple of A '1u. O B. The statement is true. Checking whether a given vector u is in fact an eigenvector is easy because it only requires checking that u is a nonzero vector and finding the pivots of M. O C. The statement is true. Checking whether a given vector u is in fact an eigenvector is easy because it only requires checking that u is a nonzero vector and finding if Au is a scalar multiple of U. O D. The statement is false. Checking whether a given vector u is in fact an eigenvector is difcult because it requires checking that u is a nonzero vector, finding all the eigenvalues ofA, then seeing if some vector formed using the eigenvalues is a scalar multiple of u