Question: A Java problem. Complete the class Tiles which manages an ArrayList of Rectangles. Each rectangle represents a ceramic floor tile. Tiles contains a constructor and

A Java problem. Complete the class Tiles which manages an ArrayList of Rectangles. Each rectangle represents a ceramic floor tile. Tiles contains a constructor and methods to process the rectangles

Provide a constructor that initializes the instance variable with an empty array list. Call the instance variable tiles.

Provide methods

1. add(Rectangle r) which adds a Rectangle object to the Tiles

2. totalArea() gets the sum of the areas of all the Rectangles in this Tiles

3. largest() gets the Rectangle with the largest area. If more than one Rectangle has the same ares, return the first.

4. toString() gets a string representation of the object. This is given to you

5. a private helper method area(Rectangle r) to get the area of a Rectangle. Use the helper method in the implementation of totalArea() and largest()

There is the Tiles(part of) and TilesTester, please complete the class Tiles.

Tiles.java

import java.util.ArrayList;

import java.awt.Rectangle; public class Tiles { public String toString() { return tiles.toString(); } }

TilesTester.java

public class TilesTester { public static void main(String[] args) { Tiles rectangles = new Tiles(); rectangles.largest(); //should not throw an exception System.out.println(rectangles.totalArea()); System.out.println("Expected: 0.0"); //add some rectangles rectangles.add(new Rectangle(0, 0, 20, 75)); rectangles.add(new Rectangle(0, 0, 100, 50)); rectangles.add(new Rectangle(0, 0, 80, 40)); rectangles.add(new Rectangle(0, 0, 50, 100)); rectangles.add(new Rectangle(0, 0, 50, 50)); Rectangle max = rectangles.largest(); if (max != null) { System.out.println("Largest: " + max); System.out.println("Expected: Rectangle[x=0,y=0,width=100,height=50]"); } double area = rectangles.totalArea(); System.out.println("total area: " + area); System.out.println("Expected: 17200.0"); } } 

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