A kitchen magnet of mass m= 2 kg is placed on a refrigerator. The magnet generates a force of F(m)=53 N, which pushes it against the fridge. You begin pushing the magnet up at some constant velocity up the door of the fridge. Assuming the coefficient of kinetic friction μk =0.254 what force must you be exerting?

 

Transcribed Image Text:

TE V m F m fridge door TE V m F m fridge door

Answer rating: 100% (QA)

Forces acting on the magnet Weight mg This force pulls the magnet downwards due to gravity It ... View the full answer