A liquid phase reaction, $A+BC+D$ is to be carried out in a well$-$mixed ideal batch reactor with a constant volume of $10$ liters. The initial concentration of $A$ is $5\mathrm{.}96mo\frac{l}{L},$ and the initial concentration of $B$ is one half of the initial concentration of $A.$ If the rate of formation of compound $D$ is given by $r_D=k^{**}{C}_A**C_B,$ with $k=4\mathrm{.}5\frac{L}{\text{m}\text{o}\text{l}\text{m}\text{i}\text{n}},$ calculate the amount of time $($in minutes$)$ needed to achieve a conversion of the limiting reactant of $0\mathrm{.}96.$ Please express your answer to two decimal places. Hint: Remember to determine the limiting reactant!

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$0\mathrm{.}19$ margin of error $+1-0\mathrm{.}02$