Question: A long string carries a wave; an 8 . 0 0 - m segment of the string contains six complete wavelengths and has a mass

A long string carries a wave; an 8.00-m segment of the string contains six complete wavelengths and has a mass of 180 g. The string vibrates sinusoidally with a frequency of 57.0 Hz and a peak-to-valley displacement of 13.0 cm.(The "peak-to-valley" distance is the vertical distance from the farthest positive position to the farthest negative position.)
(a) Write the function that describes this wave traveling in the positive x direction.
(b) Determine the power being supplied to the string.
Part 1 of 7- Conceptualize:
Notice what information we are given in this problem. We have a representative length
L =8.00 m
of the string and the number
n =6
of wavelengths in it, allowing us to find the wavelength of the wave. The mass given in the problem statement for that segment is m. The length L of the segment of the string is also the length L of a segment of the wave that contains n wavelengths. The segment of string stays fixed in its horizontal position while the segment of the wave moves along the string with a constant speed. We are also given the frequency f of the wave and the peak-to-valley distance, which we will call d.
Part 2 of 7- Categorize:
There is no particle, rigid object, or system described in this problem on which to base an analysis model. There is a wave, and we apply the only wave model we have seen so far, the traveling wave analysis model from this chapter.
Part 3 of 7- Analyze:
(a) Write the function that describes this wave traveling in the positive x direction.
(1) In terms of the quantities given in the problem statement and denoted by the symbols indicated in the Conceptualize step, write a symbolic expression as a function of position x and time t for the wave described in the problem.
y = d sin
2n
L
x 2ft
y =
d
2
sin
2n
L
x
2
T
t
correct
y =
d
2
sin
2n
L
x 2ft
y =
d
2
sin
2
L
x 2ft
none of the above
Correct: Your answer is correct.
Correct. This is the correct expression for the wave.
Part 4 of 7- Analyze: (cont.)
(2) Based on the correct choice in question (1), substitute numerical values in the following expression for the wave as a function of position x and time t, with length units in meters and time in seconds. Do not perform any calculations in this step; simply substitute the numerical values in the correct positions.
y =
d
2
sin
2n
L
x 2ft
=
0.13
Correct: Your answer is correct.
seenKey 0.13 m
2
sin
26
Correct: Your answer is correct.
seenKey 6
8
Correct: Your answer is correct.
seenKey 8.00 m
x
2
57
Correct: Your answer is correct.
seenKey 57.0
t
Part 5 of 7- Analyze: (cont.)
(3) Now perform the calculations in question (2) to determine the functional expression for the wave described in the problem. Substitute the results of those calculations in the expression below.
y = A sin(kx t)
=
Incorrect with feedback: Your answer is incorrect. Click to see feedback.
m
sin
Incorrect with feedback: Your answer is incorrect. Click to see feedback.
m1
x
Incorrect with feedback: Your answer is incorrect. Click to see feedback.
s1
t

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