A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 10802 dollars.

How much did he invest at each rate? Set up and solve a systems of equations to answer this question.



The total invested in the account paying 6 percent interest is  
The total invested in the account paying 10 percent interest is

Answer rating: 100% (QA)

Let the total invested in the account paying n dollars and that in the acco... View the full answer