1. A man (m= 80 kg) grips a hand drill (m 5 kg) parallel to the...

 

 

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1. A man (m= 80 kg) grips a hand drill (m 5 kg) parallel to the ground, as shown below. The extensor carpi radialis (ECR), that is, the wrist muscle, counteracts the weight of the drill in order to hold it parallel to the ground. ECR generates a force (FECR) of 295 N located at a distance of Li and height of Ax. WA is the weight of the lower arm located at L2/2. Wp is the weight of the drill. a. Draw a Free Body Diagram (FBD) of the system b. Compute the vertical force of the biceps muscle (FB) e Compute the vertical and horizontal reaction forces (Ry and R) at the elbow in order to hold the forearm parallel to the ground EMo o も、tve FB Efy0 Ax Fret 1em Free Wp WA TH L2 →+ム+ 11 m FB Ax Frret YWD WA -L2- L2 = 30 cm L3 = 6 cm Ax = 2 cm %3D L = 12 cm %3D %3D 1. A man (m= 80 kg) grips a hand drill (m 5 kg) parallel to the ground, as shown below. The extensor carpi radialis (ECR), that is, the wrist muscle, counteracts the weight of the drill in order to hold it parallel to the ground. ECR generates a force (FECR) of 295 N located at a distance of Li and height of Ax. WA is the weight of the lower arm located at L2/2. Wp is the weight of the drill. a. Draw a Free Body Diagram (FBD) of the system b. Compute the vertical force of the biceps muscle (FB) e Compute the vertical and horizontal reaction forces (Ry and R) at the elbow in order to hold the forearm parallel to the ground EMo o も、tve FB Efy0 Ax Fret 1em Free Wp WA TH L2 →+ム+ 11 m FB Ax Frret YWD WA -L2- L2 = 30 cm L3 = 6 cm Ax = 2 cm %3D L = 12 cm %3D %3D