A mass of 0.41 kg is initially at rest on a hor- izontal surface. A force,...
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A mass of 0.41 kg is initially at rest on a hor- izontal surface. A force, given by F = F , acts on the mass. The horizontal component F is plotted below as a function of position along the x-axes. The coefficient of kinetic friction is 0. The acceleration of gravity is 9.8 m/s. 5 3 Z2 Force (N) -2 0 1 2 3 4 5 6 7 8 9 10 - position (m) Calculate the kinetic energy K of the mass as it reaches 6 m. Answer in units of J. A mass of 0.41 kg is initially at rest on a hor- izontal surface. A force, given by F = F , acts on the mass. The horizontal component F is plotted below as a function of position along the x-axes. The coefficient of kinetic friction is 0. The acceleration of gravity is 9.8 m/s. 5 3 Z2 Force (N) -2 0 1 2 3 4 5 6 7 8 9 10 - position (m) Calculate the kinetic energy K of the mass as it reaches 6 m. Answer in units of J.
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Summation Energy of Areas under curve gives us the kinetic Kinetic Energy at position Im 3... View the full answer
Related Book For
University Physics with Modern Physics
ISBN: 978-0321696861
13th edition
Authors: Hugh D. Young, Roger A. Freedman, A. Lewis Ford
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