A mobile transmits at 50 mW with an antenna gain of -1 dBi to a base...

 

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A mobile transmits at 50 mW with an antenna gain of -1 dBi to a base station with a receive antenna gain of 15 dBi. The data rate is 100 Mbps and the channel bandwidth is 20 MHz. The path loss at a reference distance d0 = 100 m (NOT counting the transmit and the receive antenna gains) is 82 dB and the path loss exponent is 5 in this area. a) (2 marks) What is the SNR at the reference distance d0 (assume noise PSD is No-KT W/Hz). b) (3 marks) If the system needs a minimum average bit SNR of 10 dB to function and the maximum transmit power of the mobile is 100mW, what is the maximum radius of a cell? (3 marks) Assume the shadowing effect has a standard deviation of o-6 dB and we plan to ensure reliable communication as long as the shadowing is within 20 range, what is the maximum radius of the cell? c) d) (2 marks) When the operator provides actual services by placing base station and planning for the cell size, the radius of the actual cell is only 1/2 of the answer in part. Can you think of the two most probably reasons why the operator plans such a small cell? A mobile transmits at 50 mW with an antenna gain of -1 dBi to a base station with a receive antenna gain of 15 dBi. The data rate is 100 Mbps and the channel bandwidth is 20 MHz. The path loss at a reference distance d0 = 100 m (NOT counting the transmit and the receive antenna gains) is 82 dB and the path loss exponent is 5 in this area. a) (2 marks) What is the SNR at the reference distance d0 (assume noise PSD is No-KT W/Hz). b) (3 marks) If the system needs a minimum average bit SNR of 10 dB to function and the maximum transmit power of the mobile is 100mW, what is the maximum radius of a cell? (3 marks) Assume the shadowing effect has a standard deviation of o-6 dB and we plan to ensure reliable communication as long as the shadowing is within 20 range, what is the maximum radius of the cell? c) d) (2 marks) When the operator provides actual services by placing base station and planning for the cell size, the radius of the actual cell is only 1/2 of the answer in part. Can you think of the two most probably reasons why the operator plans such a small cell?

Answer rating: 100% (QA)

a To calculate the SNR at the reference distance d0 we need to consider the received power and the noise power The received power can be calculated using the path loss formula Prd Pt Ld where Prd is t... View the full answer