A multiple regression with 39 observations and five explanatory variables yields the ANOVA table. ANOVA Table Degrees of Sum of Squares Freedom Explained 1,832 Unexplained Total 3,524 a. Complete this ANOVA table. Round your answers for mean of squares and F to three decimal places and for p-Value to four decimal places, if necessary. ANOVA Table Degrees of Sum of Squares Mean of Squares Freedom F p-Value Explained 1,832 Unexplained Total 3,524 b. Can you conclude at the 1% significance level that these five explanatory variables have some power in explaining variation in the dependent variable? Select v because the p-value is Select v than 0.01, we Select v reject the null hypothesis about the Select of Select y power. Yes NoA multiple regression with 39 observations and five explanatory variables yields the ANOVA table. ANOVA Table Degrees of Sum of Squares Freedom Explained 1,832 Unexplained Total 3,524 a. Complete this ANOVA table. Round your answers for mean of squares and F to three decimal places and for p-Value to four decimal places, if necessary. ANOVA Table Degrees of Sum of Squares Mean of Squares Freedom F p-Value Explained 1,832 Unexplained Total 3,524 b. Can you conclude at the 1% significance level that these five explanatory variables have some power in explaining variation in the dependent variable? Select v , because the p-value is Select than 0.01, we Select v reject the null hypothesis about the Select V of explanatory power. Select less greaterA multiple regression with 39 observations and five explanatory variables yields the ANOVA table. ANOVA Table Degrees of Sum of Squares Freedom Explained 1,832 Unexplained Total 3,524 a. Complete this ANOVA table. Round your answers for mean of squares and F to three decimal places and for p-Value to four decimal places, if necessary. ANOVA Table Degrees of Sum of Squares Mean of Squares Freedom F p-Value Explained 1,832 Unexplained Total 3,524 b. Can you conclude at the 1% significance level that these five explanatory variables have some power in explaining variation in the dependent variable? Select v , because the p-value is Select v than 0.01, we Select v reject the null hypothesis about the Select of explanatory power. Select can cannotA multiple regression with 39 observations and five explanatory variables yields the ANOVA table. ANOVA Table Degrees of Sum of Squares Freedom Explained 1,832 Unexplained Total 3,524 a. Complete this ANOVA table. Round your answers for mean of squares and F to three decimal places and for p-Value to four decimal places, if necessary. ANOVA Table Degrees of Sum of Squares Mean of Squares Freedom F p-Value Explained 1,832 Unexplained Total 3,524 b. Can you conclude at the 1% significance level that these five explanatory variables have some power in explaining variation in the dependent variable? Select v, because the p-value is Select v than 0.01, we Select v reject the null hypothesis about the Select of explanatory power. Select presence absenceA multiple regression with 39 observations and five explanatory variables yields the ANOVA table. ANOVA Table Degrees of Sum of Squares Freedom Explained 1,832 Unexplained Total 3,524 a. Complete this ANOVA table. Round your answers for mean of squares and F to three decimal places and for p-Value to four decimal places, if necessary. ANOVA Table Degrees of Sum of Squares Mean of Squares Freedom F p-Value Explained 1,832 Unexplained Total 3,524 b. Can you conclude at the 1% significance level that these five explanatory variables have some power in explaining variation in the dependent variable? Select v , because the p-value is Select v|than 0.01, we select |reject the null hypothesis about the Select of explanatory power