Question: A n- (pi-minus) particle, which has charge -e, is at location m. What is the electric field at location m, due to the n- particle?

 A n- ("pi-minus") particle, which has charge -e, is at location

A n- ("pi-minus") particle, which has charge -e, is at location m. What is the electric field at location m, due to the n- particle? E = newton/coulomb X An antiproton (same mass as the proton, charge -e) is at the observation location. What is the force on the antiproton, due to the n-? F = newton

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