A new open$-$source system $($intended for asynchronous systems$)$ uses a leader election

protocol in a group of $N$ processes that is akin to the following $($you can assume that no

additional processes join, fail from, or leave the group during the election$).$ When a process

discovers the leader has failed, it initiates an election. It sends out an "ElectMe!" message to

all $N-1$ processes including itself. Every process has a unique priority $($e$.$g$.,$ its id$),$ and the

ElectMe! message contains this priority. When a process receives an ElectMe! Message

$($notice that a process has to receive its own ElectMe! too and vote on it$),$ immediately it

does the following: it compares its own priority with that in the message. If its own priority

is higher, it multicasts out an ElectMe! message to everyone; otherwise it responds back

with a unicast "Vote" message. However, once a process has sent out a Vote message, it

cannot send out any more Vote or ElectMe! Messages $($i$.$e$.,$ a process can vote at most once$).$

A process also can send out at most one ElectMe! message. Finally, when a process receives

at least $2\frac{N}{3}($i$.$e$.,$ a super$-$majority of N$)$ Vote messages, it declares itself as a leader.

There may be multiple correct answers below. Given that safety requires only the highest$-$

priority process to be elected and everyone to know about this new leader, this protocol is

$($MULTIPLE answers$)$: $(1$ point$)$

Not safe

Not enough information to reason about liveness

Safe

Not live