A paint can opener is 0.126 m from the holding end to the pivot point, and 0.0050 m from the pivot point to the lid opening end. If you apply 150 N of force to the holding end, how much force in N will the can opener exert against the can lid to two significant digits?

Answer rating: 100% (QA)

The turning force is F x d The pivot point is the central axis of the can ... View the full answer