Question: A Parallel plate capacitor is charged fully using a 30 V battery such that the charge on it is 140 pC and the plate
A Parallel plate capacitor is charged fully using a 30 V battery such that the charge on it is 140 pC and the plate separation is 5 mm. The capacitor is then disconnected from the battery and the plate separation doubled. What is: The new charge on the plates after the separation is increased Number The new potential difference between the plates 60 The Field between the plates after increasing the separation 6000 N/C How much work does one have to do to pull the plates apart. Number J
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First we can calculate the capacitance of the capacitor using the formula C Q V where C capacitance ... View full answer
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