Question: A particle is executing circular motion with a constant angular frequency of = 4 . 3 3 rad / s . If time t =

A particle is executing circular motion with a constant angular frequency of
=4.33 rad/s.
If time
t =0
corresponds to the position of the particle being located at
y =0
and
x =6.2 m,
answer the following. (Express your answers in vector form.)
(a)
What is the position of the particle (in m) at
t =12 s?
r =
(0.884i+6.138j)
m
(b)
What is its velocity (in m/s) at this time?
v =
(26.89i3.63j)
m/s
(c)
What is its acceleration (in m/s2) at this time?
a =
(15.85i114.37j)
m/s2

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