Question: A particle moves along the ( x ) axis. It is initially at the position 0 . 2 9 0 m , moving

A particle moves along the \( x \) axis. It is initially at the position 0.290 m , moving with velocity \(0.210\mathrm{~m}/\mathrm{s}\) and acceleration \(-0.350\mathrm{~m}/\mathrm{s}^{2}\). Suppose it moves with constant acceleration for 5.50 s .
(a) Find the position of the particle after this time.
m
(b) Find its velocity at the end of this time interval.
\(\checkmark \mathrm{m}/\mathrm{s}\)
Next, assume it moves with simple harmonic motion for 5.50 s and \( x=0\) is its equilibrium position. (Assume that the velocity and acceleration is the same as in parts (a) and (b).)
(c) Find its position.
The response you submitted has the wrong sign. m
(d) Find its velocity at the end of this time interval.
\(\mathrm{m}/\mathrm{s}\)
A particle moves along the \ ( x \ ) axis. It is

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