A particle moves through an xyz coordinate system while a force acts on it$.$ When the particle has the position vector

$=(2\mathrm{.}00$ m$)(3\mathrm{.}00$ m$)+(2\mathrm{.}00$ m$),$

the force is

$=$ Fx $+(7\mathrm{.}00$ N$)(6\mathrm{.}70$ N$)$

and the corresponding torque about the origin is

$=(6\mathrm{.}10$ N $$ m$)+(3\mathrm{.}20$ N $$ m$)+(1\mathrm{.}30$ N $$ m$).$

Determine Fx$.$