Question: A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2.00

A particle moves through an xyz coordinate system while a force acts on the particle. When the particle has the position vector r = (2.00 m) i - (3.00 m) j + (2.00 m) k, the force is F = F xi + (7.00N) j – (6.00 N) k and the corresponding sponding torque about the origin is r = (4.00 N ∙ m) i + (2.00 N ∙ m) j - (1.00 N ∙ m) k. Determine F x

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Eq 1114 along with Eq 330 gives trxF 400 120 200F 140 300Fk ... View full answer

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