Question: A particle moving in simple harmonic motion passes through the equilibrium point (x=0) 2 times per second. At t=0 its velocity at x=0.04 m is
A particle moving in simple harmonic motion passes through the equilibrium point (x=0) 2 times per second. At t=0 its velocity at x=0.04 m is negative. It travels 0.4 m in a complete cycle. The particle's position as a function of time is described by the following function: x(t)= sin(t + ) cm
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