Question: A phagehunter performs a full plate titer experiment and observes a webbed plate at the 10- dilution but the phagehunter estimates an ideal webbed plate

A phagehunter performs a full plate titer
A phagehunter performs a full plate titer experiment and observes a webbed plate at the 10- dilution but the phagehunter estimates an ideal webbed plate would be 2x as concentrated. Assume standard techniques (100 ul of each 10-fold phage dilution added to 250 uL of Gordonia terrae host cells) were used. Assume no more than 300 ul of lysate can be mixed with host cells. How much phage should the experimenter add in order to create an optimum webbed plate? Select one answer only. 200 ul of a 10-2 dilution 20.0 ul of a 10-1 dilution 2.00 ul of a 10 dilution 200 ul of a 10-1 dilution 100 ul of a 10-1 dilution 100 ul of a 10-2 dilution 175 ul of a 10-1 dilution 100 ul of a 10-3 dilution 20.0 ul of a 10-3 dilution A phagehunter performs a full plate titer experiment and observes a webbed plate at the 10-4 dilution but the phagehunter estimates an ideal webbed plate would be 1.25X as concentrated. Assume standard techniques (100 ul of each 10-fold phage dilution added to 250 uL of Gordonia terrae host cells) were used. Assume no more than 300 ul of lysate can be mixed with host cells. How much phage should the experimenter add in order to create an optimum webbed plate? Select one answer only. 12.5 ul of a 10-5 dilution 100 ul of a 10-5 dilution 125 ul of a 10-5 dilution 12.5 ul of a 10-4 dilution 100 ul of a 10-3 dilution 125 ul of a 10-4 dilution 125 ul of a 10-3 dilution 1.25 ul of a 10-3 dilution 100 ul of a 10-4 dilution

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