Question: A P-N junction diode with T = 100ns conducts a forward-bias current I D = 4.3 mA. At time t = 0, the circuit
A P-N junction diode with τ T = 100ns conducts a forward-bias current I D = 4.3 mA. At time t = 0, the circuit conditions change, so that a reverse-bias voltage V E = 20V is connected in series with the diode and resistor R = 1 kΩ.
A P-N junction diode with tT = 100 ns conducts a forward-bias current Ip = 4.3 mA. At time i = 0, the circuit conditions change, so that a reverse-bias voltage VE = 20 V is connected in series with the diode and a resistor R = 1 k2. (a) Because of the strong discharging current (~ 20.7 V/1 k2 = 20.7 mA), the contribution of %3D %3D the recombination to the stored charge removal can be neglected. How long will it take for the stored charge to be removed? (b) If VE = 0, the diode is discharged with a much smaller current ( 0.7 V/1 kN = 0.7 mA), so that the contribution from the recombination cannot be neglected. If it is found that it takes trs = 200 ns for the stored charge to be removed, how much stored charge is removed by recombination? A
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