A process flows through Steps A$-$D$.$ At Step A$,$ out of $100$ good units arriving, $100$ good units are sent to B including $10$ repaired units. So $0$ units are scrapped at step A Le Repair proportion $($RP$)$ at A $10\%(10$ units repaired out of incoming $100$ units$)$ Step B $($Out of $100$ units reed from A$)90$ good units are sent to C including $6$ repaired units So $10$ units are scrapped at Step B$.$ RP at B$6$ repaired$/100$ recd$-6\%$ Step C $($Out of $90$ good units reed from B$)87$ good units are sent to D including $15$ repaired units $3$ units are scrapped at C: RP$-15/90-16\mathrm{.}67\%$ Step D $($Out of $87$ good units reed from C$),85$ good units come out of D including $5$ repaired units $2$ units are scrapped at D: RP$-5/87-5756$ The FPY $($first pass yield$)$ of Step C is approx? FPY$/$FTY of a work step $=[($Total units received at station minus repaired and or scrap $0\mathrm{.}920\mathrm{.}860800\mathrm{.}34$