Question $2$

A process flows through Steps A$-$D$.$

At Step A$,$ out of $100$ good units arriving, $100$ good units are sent to B including $10$ repaired units.

So $0$ units are scrapped at step $A$

i$.$e$.,$ Repair proportion $(RP)$ at $A=10\%(10$ units repaired out of incoming $100$ units$)$

Step B $($Out of $100$ units recd from A$)90$ good units are sent to $C$ including $6$ repaired units. ${?}_{(})$

So $10$ units are scrapped at Step B$.$ RP at B $=6$ repaired $\frac{?}{100\text{r}\text{e}\text{c}\text{d}}=6\%$

Step C $($Out of $90$ good units recd from B$)87$ good units are sent to D including $15$ repaired units.

$3$ units are scrapped at $C$;$RP=\frac{15}{90}=16\mathrm{.}67\%$

Step D $($Out of $87$ good units recd from C$),85$ good units come out of D including $5$ repaired units.

$2$ units are scrapped at $D$;$RP=\frac{5}{87}=5\mathrm{.}75\%$

The FPY $($first pass yield$)$ of Step $C$ is approx?

$0\mathrm{.}92$

FPY$/$FTY of a work step $=[($Total units received at station minus # repaired and$/$or scrapped